Wednesday, March 28, 2012

Problems on Clocks

Download Clock Study Material           
Problems :

1)     1) Find the angle between Hour hand and minute hand of a clock when the time is 3.25 ?
     Solution :  Angle=|(11*m/2)-(30h)| = |(11*25/2)-(30*3)|=47.5 degrees

2)      2) At What time between 2 and 3 o’clock will hands  of a clock together ?
 Solution : If the Both the hands are together means angle between the clock is zero(0).Let the hour is at 2 o’clock.

           Angle=|(11*m/2)-(30h)|
            0=|(11m/2)-(30*2)|
11m/2=60
M=60*2/11=10 10/11 mins. 

              Hence the two hands are meet at 10 10/11 mins past 2.

      3) Find the angle between Hour hand and minute hand of a clock when the time is 8:30 ?
Solution :  Angle=|(11*m/2)-(30h)|
                                 = |(11*30/2)-(30*8)|=|165-240|= 75 degrees
  
     4)How many times do the hands  of a clock coincide in a day ?
 Solution : 22 times (Every 12 hours 11 times they are meeting)
     
     5)At What time between 7 and 8 o’ clock will the hands of a clock be in the same straight line but not together ?
 Solution : hands of a clock be in the same straight line but not together means angle is 180 degrees.
Let the hour is at 7 o’clock.
           Angle=|(11*m/2)-(30h)|
           180=|(11m/2)-(30*7)|
11m/2=180+210 or 11m/2=-180+210
11m/2=390 or 11m/2=30
m=780/11 or m=60/11
m= 72 8/11 or 5 5/11 mins.
        Hence the time will be either 72 8/11 mins past 7or 5 5/11 mins past 7 
     6) A clock loses 5 min for every hour and another clock gains 5 min for every hour .If they are set correct at 10 am on Monday then when will they be 12 hrs apart ?
Solution : for every hour watch A loses 5 min and watch B gains 5 mins.
So for every hour they will differ by 10 mins.
For 12 hours (720 mins ) difference between them is =720/10 =72 mins.
So they will be 12 hrs apart after 3 days i.e: at 10 am on Thurs day

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